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x={-b\pm\sqrt{b^2-4ac} \over 2a}}

\left( \frac{\left(3-x\right) \times 2}{3-x} \right)

\frac{3}{8}

a^2+b^2=c^2

\frac{3}{8} + \frac{3}{8}

\left({\left(3-x\right) \times 2}\right)

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